Hess Law Lab

Objective To determine of arouse ups from three exothermic fightions and check the Hess Law Summary Based on this audition, we have get three related exothermic receptions involving atomic number 11 hydroxide. The first reception (Part A), steadfast atomic number 11 hydroxide give decouple into body of water. The heat prove by this answer (?H1) and this called as the heat of solvent of straight NaOH. From the test we have managed to intractable that ?H1 = -41.84 KJ/mol In the foster reaction (Part B), an aqueous solution of NaOH is allowed to react with an aqueous solution of HCl. This is a neutralization reaction in the midst of a strong acid and strong base. Therefore the heat of reaction (?H2) is called as the heat of neutralization of HCl and NaOH solutions. The ?H2 calculated from this experiment is -6.6944KJ/mol. This is because the hydrogen changes when 1 bulwark of H+ ions from an acid (HCl) reacts with one mole of OH- fro m an alkali (NaOH) to form one mole of water molecules under the stated conditions of the experiment. In the final reaction of the experiment (Part C), whole NaOH willing react with an aqueous solution of HCl. This reaction is to a fault the combination of the first and two reactions. The solid NaOH will dissociate into its ions as it dissolves in the acid solution which is thence change by the acid solution.

Thus the heat of the reaction (?H3) is state be equal to (?H1+?H2). It is called the heat of solution of solid NaOH. From our computation it known that ?H3 is -58.6 kJ/mol. When ionic solid dissolves in water, heat was librated. chemical reacti! on 1: Dissolving solid sodium hydroxide in water. NaOH(s) ---> Na+(aq) + OH-(aq) + heat Reaction 2: Reaction of sodium hydroxide solution with dilute hydrochloric acid. Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) ---> Na+(aq) + Cl-(aq) + H2O Reaction 3: Reaction of solid sodium hydroxide with dilute hydrochloric acid solution....If you want to get a blanket(a) essay, order it on our website: OrderCustomPaper.com

If you want to get a full essay, visit our page: write my paper